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Unit F3 Section 3
Linear Factorisation

The process of removing brackets is known as expanding. The reverse process is known as factorisation, where an expression is rewritten as a product of terms.

To factorise an expression it is necessary to identify numbers or variables which are factors common to all the terms.

Worked Examples

1

Factorise 6x + 8.

Both terms (6x) and (8) can be divided by 2, so the expression is factorised as

6x + 8 = (2 × 3x) + (2 × 4)
= 2(3x + 4)
2

Factorise 12a − 16.

Here the largest number by which both terms, (12a) and (16), can be divided is 4.

12a − 16 = (4 × 3a) − (4 × 4)
= 4(3a − 4)
3

Factorise 4x2 − 8x .

Here 4 is the largest number that will divide both terms, but each term can also be divided by x, so 4x is the factor common to both terms.

4x2 − 8x = (4x × x) − (4x × 2)
= 4x(x − 2)

Exercises

Copy and complete each of the following.

(a)
5x + 10 = (x + 2)
(b)
6x − 8 = (3x − 4)
(c)
15x + 25 = (3x + 5)
(d)
12x + 8 = 4( + )
(e)
18 − 6n = 6()
(f)
6x − 21 = 3()
(g)
16a + 24 = 8( + )
(h)
33x − 9 = 3()

Factorise each of the following expressions.

(a)
6x + 24
(b)
5x − 20
(c)
16 − 8x
(d)
8n + 12
(e)
12x − 14
(f)
3a − 24
(g)
11x − 66
(h)
10 + 25x
(i)
100x − 40
(j)
50 − 40x
(k)
6x − 30
(l)
5y − 45
(m)
12 + 36x
(n)
16x + 32
(o)
27x − 33

Factorise each of the following expressions.

(a)
5x2 + x
(b)
a2 + 3a
(c)
5n2 + 2n
(d)
6n2 + 3n
(e)
5n2 − 10n
(f)
3x2 + 6x
(g)
15x2 + 30x
(h)
14x2 + 21x
(i)
16x2 + 24x
(j)
30x2 − 18x
(k)
5 + 5n2
(l)
10n2 − 15
(m)
3n3 + 9n
(n)
9x2 − 27x
(o)
10x3 − 5x2

Factorise each of the following expressions.

(a)
ax + ax2
(b)
bx + cx2
(c)
2pq − 4rq
(d)
15xy − 5y2
(e)
16pq + 24p2
(f)
6x2 + 18xy
(g)
3p2 − 9px
(h)
24px + 56x2
(i)
16x2y − 18xy2