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Unit B1 Section 3
Estimating Number Patterns
A formula or rule for extending a sequence can be used to work out any term of a sequence without working out all the terms. For example, the 100th term of the sequence,
1, 4, 7, 10, 13, ...
can be calculated as 298 without working out any other terms.
Worked Examples
1
Find the 20th term of the sequence
8, 16, 24, 32, ...
The terms of the sequence can be obtained as shown below.
| 1st term | = 1 × 8 | = 8 |
| 2nd term | = 2 × 8 | = 16 |
| 3rd term | = 3 × 8 | = 24 |
| 4th term | = 4 × 8 | = 32 |
This pattern can be extended to give
20th term = 20 × 8 = 160
2
Find the 10th and 100th terms of the sequence
3, 5, 7, 9, 11, ...
The terms above are given by
| 1st term | = 3 |
| 2nd term | = 3 + 2 = 5 |
| 3rd term | = 3 + 2 × 2 = 7 |
| 4th term | = 3 + 3 × 2 = 9 |
| 5th term | = 3 + 4 × 2 = 11 |
This can be extended to give
| 10th term | = 3 + 9 × 2 = 21 |
| 100th term | = 3 + 99 × 2 = 201 |
3
Find the 20th term of the sequence
2, 5, 10, 17, 26, 37, ...
The terms of this sequence can be expressed as
| 1st term | = 12 + 1 |
| 2nd term | = 22 + 1 |
| 3rd term | = 32 + 1 |
| 4th term | = 42 + 1 |
| 5th term | = 52 + 1 |
Extending the pattern gives
20th term = 202 + 1 = 401

